Calculate how many times you can travel around the earth using 1.228x10^2GJ with an E-scooter which uses 3 kWh per 100 km. Note that you can travel to the sun and back with this scooter using the energy of a whole year.

A) The collision described is an inelastic collision because the bullet becomes embedded in the clay, and they move together as one mass after the collision.

B) In an inelastic collision, the total momentum is conserved.

However, some kinetic energy is lost in the process due to deformation and other factors.

C) Momentum is defined as the product of an object's mass and velocity. Mathematically, momentum (p) is given by the equation: p = m * v, where m is the mass of the object and v is its velocity.

The SI unit for momentum is kilogram-meter per second (kg·m/s).

D) To determine the original speed of the bullet, we can use the principle of conservation of momentum. In an inelastic collision, the total momentum before the collision is equal to the total momentum after the collision.

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The phase angle o between V and I is  27.6 degree

To determine the phase angle (θ) between voltage (V) and current (I) in an RLC series circuit, we need to calculate the impedance (Z) and the phase angle associated with it.

The impedance (Z) of an RLC series circuit can be calculated using the formula:

Z = √(R² + (XL - XC)²)

Where:

R = resistance (50 Ω)

XL = inductive reactance (ωL)

XC = capacitive reactance (1 / ωC)

ω = angular frequency (2πf)

f = frequency (50 Hz)

L = inductance (28 mH = 0.028 H)

C = capacitance (120 μF = 0.00012 F)

ω = 2πf = 2π * 50 = 100π rad/s

XL = ωL = 100π * 0.028 = 2.8π Ω

XC = 1 / (ωC) = 1 / (100π * 0.00012) = 1 / (0.012π) = 100 / π Ω

Now, let's calculate the impedance (Z):

Z = √(50² + (2.8π - 100/π)²)

Using a calculator, we find:

Z ≈ 50.33 Ω

The phase angle (θ) can be calculated using the formula:

θ = arctan((XL - XC) / R)

θ = arctan((2.8π - 100/π) / 50)

Using a calculator, we find

θ ≈ 0.454 rad

To convert the angle to degrees, we multiply it by (180/π):

θ ≈ 0.454 * (180/π) ≈ 26.02°

Therefore, the phase angle (θ) between V and I is approximately 26.02°.

Among the given options, the closest value to 26.02° is 27.6° (option c)

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The difference in the gravitational fields acting on the occupants in the nose of the ship and on those in the rear of the ship, farthest from the black hole can be calculated using the equation for gravitational field strength:
g = (G * M) / r^2

Where g is the gravitational field strength, G is the gravitational constant, M is the mass of the black hole, and r is the distance between the occupants and the center of the black hole. Since the mass of the black hole is 100 times that of the Sun, we can assume it to be approximately 1.989 x 10^31 kg.

The distance between the nose of the spacecraft and the center of the black hole is given as 10.0 km, which can be converted to 10,000 m. Plugging these values into the equation, we can calculate the gravitational field strength at the nose of the ship and at the rear of the ship. The difference between these two values will give us the difference in gravitational fields acting on the occupants. Note that as the ship approaches the black hole, this difference in accelerations will increase rapidly, eventually tearing the ship apart due to extreme tension.

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The actual frequency of the ambulance's siren is approximately 481.87 Hz.

To determine the actual frequency of the ambulance's siren, we need to consider the Doppler effect. The Doppler effect describes the change in frequency of a wave when the source of the wave and the observer are in relative motion.

In this case, you are driving towards the ambulance, so you are the observer. The ambulance's siren is the source of the sound waves. When the source and the observer are moving toward each other, the observed frequency is higher than the actual frequency.

We can use the Doppler effect formula for sound to calculate the actual frequency:

f' = (v + vo) / (v + vs) * f

Where:

f' is the observed frequency

f is the actual frequency

v is the speed of sound

vo is the velocity of the observer

vs is the velocity of the source

Given that you are driving at a velocity of 37 m/s towards the ambulance, the ambulance is traveling at a velocity of 44 m/s towards you, and the observed frequency is 426 Hz, we can substitute these values into the formula:

426 = (v + 37) / (v - 44) * f

To solve for f, we need the speed of sound (v). Assuming the speed of sound is approximately 343 m/s, which is the speed of sound in dry air at room temperature, we can solve the equation for f:

426 = (343 + 37) / (343 - 44) * f

Simplifying the equation, we get:

426 = 380 / 299 * f

f ≈ 481.87 Hz

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The spring constant of the system is 30 N/m.

To determine the spring constant, we can use Hooke's Law, which states that the force exerted by a spring is proportional to the displacement from its equilibrium position. Mathematically, this can be expressed as F = -kx, where F is the force applied, k is the spring constant, and x is the displacement.

In this case, the spring stretches from 80 cm to 95 cm, which means the displacement is 15 cm (or 0.15 m). The force applied can be calculated using the weight of the copper mass hanging on the spring. The weight of an object can be determined using the formula W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Given that the mass of the copper is 350 g (or 0.35 kg) and the acceleration due to gravity is approximately 9.8 m/s², the weight of the copper is W = 0.35 kg × 9.8 m/s² = 3.43 N.

Now we can substitute the values into Hooke's Law to find the spring constant:

3.43 N = -k × 0.15 m

Solving for k, we get:

k = 3.43 N / -0.15 m

k ≈ 22.87 N/m

Rounding to the nearest whole number, the spring constant is approximately 23 N/m.

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The minimum acceleration needed for the plane to take flight is 1.45 m/s² (to 2 decimal places).

Given:To take off, an airplane needs to reach a speed of 215 km/h.

The runway available is 1738 m. To find:

Solution:Let's first convert the speed of 215 km/h to m/s.

1 km = 1000 m

∴ 215 km/h = (215 x 1000) / 3600 m/s

= 59.72 m/s

The equation of motion that relates speed, acceleration, and distance is:v² - u² = 2as

Here,

v = final velocity

u = initial velocity = 0

s = distance = 1738 m

Rearranging the equation, we get

a = (v² - u²) / 2s

Substituting the values,

a = (59.72² - 0²) / 2 x 1738

a = 1.45 m/s²

Therefore, the minimum acceleration needed for the plane to take flight is 1.45 m/s² (to 2 decimal places).

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In this experiment, the time of an hour in this experiment is a control variable.

In an experimental setup, a control is a standard against which the results of the other variables are compared. It is used to establish a baseline or reference point. In this case, the experiment aims to measure the warmth of the air in each box after being placed in the sun for an hour. The purpose of the experiment is to compare the warmth in different boxes made of different materials.

The time of an hour is kept constant and is not manipulated or changed throughout the experiment. It serves as a control to ensure that all boxes are exposed to the same duration of sunlight. By keeping the time constant, any differences in the warmth of the air in the boxes can be attributed to the material of the boxes rather than the duration of exposure to sunlight.

Therefore, the time of an hour in this experiment is a control variable.

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(a) Displacement: [tex]\(-2.325 \, \text{m}\)[/tex], (b) Velocity: [tex]\(4.28 \, \frac{\text{m}}{\text{s}}\)[/tex], (c) Acceleration: [tex]\(-48.56 \, \frac{\text{m}}{\text{s}^2}\[/tex], (d) Phase: [tex]\( \frac{\pi}{6} \, \text{rad}\)[/tex], (e) Frequency: [tex]\(2\pi \, \frac{\text{rad}}{\text{s}}\)[/tex], (f) Period: [tex]\(\frac{1}{2\pi} \, \text{s}\)[/tex]

To find the displacement, velocity, acceleration, and phase of the simple harmonic motion described by the equation [tex]\(x = (2.7 \, \text{m})\cos\left[(2\pi \, \frac{\text{rad}}{\text{s}})t + \frac{\pi}{6} \, \text{rad}\right]\) at \\\(t = 3.6 \, \text{s}\)[/tex], we can directly substitute the given time into the equation. Let's calculate each quantity:

(a) Displacement:

Substituting [tex]\(t = 3.6 \, \text{s}\)[/tex] into the equation:

[tex]\[x = (2.7 \, \text{m})\cos\left[(2\pi \, \frac{\text{rad}}{\text{s}})(3.6 \, \text{s}) + \frac{\pi}{6} \, \text{rad}\right]\][/tex]

Calculating the expression:

[tex]\[x = (2.7 \, \text{m})\cos\left[(7.2\pi + \frac{\pi}{6}) \, \text{rad}\right]\]\\\\\x = (2.7 \, \text{m})\cos\left(\frac{43\pi}{6} \, \text{rad}\right)\]\\\\\x = (2.7 \, \text{m})\cos\left(\frac{43\pi}{6} - 2\pi \, \text{rad}\right)\]\\\\\x = (2.7 \, \text{m})\cos\left(\frac{7\pi}{6} \, \text{rad}\right)\]\\\\\x = (2.7 \, \text{m})\left(-\frac{\sqrt{3}}{2}\right)\]\\\\\x \approx -2.325 \, \text{m}\][/tex]

(b) Velocity:

The velocity can be obtained by taking the derivative of the displacement equation with respect to time:

[tex]\[v = \frac{dx}{dt} = \frac{d}{dt}\left((2.7 \, \text{m})\cos\left[(2\pi \, \frac{\text{rad}}{\text{s}})t + \frac{\pi}{6} \, \text{rad}\right]\right)\][/tex]

Differentiating the expression:

[tex]\[v = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)\sin\left[(2\pi \, \frac{\text{rad}}{\text{s}})t + \frac{\pi}{6} \, \text{rad}\right]\][/tex]

Substituting \(t = 3.6 \, \text{s}\):

[tex]\[v = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)\sin\left[(2\pi \, \frac{\text{rad}}{\text{s}})(3.6 \, \text{s}) + \frac{\pi}{6} \, \text{rad}\right]\]\\\\\v = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)\sin\left(\frac{43\pi}{6} \, \text{rad}\right)\]\\\\\v \approx 4.28 \, \frac{\text{m}}{\text{s}}\][/tex]

(c) Acceleration:

The acceleration can be obtained by taking the derivative of the velocity equation with respect to time:

[tex]\[a = \frac{dv}{dt} \\\\=\frac{d}{dt}\left(-(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)\sin\left[(2\pi \, \frac{\text{rad}}{\text{s}})t + \frac{\pi}{6} \, \text{rad}\right]\right)\][/tex]

Differentiating the expression:

[tex]\[a = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)^2\cos\left[(2\pi \, \frac{\text{rad}}{\text{s}})t + \frac{\pi}{6} \, \text{rad}\right]\][/tex]

Substituting [tex]\(t = 3.6 \, \text{s}\)[/tex]:

[tex]\[a = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)^2\cos\left[(2\pi \, \frac{\text{rad}}{\text{s}})(3.6 \, \text{s}) + \frac{\pi}{6} \, \text{rad}\right]\]\\\\\a = -(2.7 \, \text{m})\left(2\pi \, \frac{\text{rad}}{\text{s}}\right)^2\cos\left(\frac{43\pi}{6} \, \text{rad}\right)\]\\\\\a \approx -48.56 \, \frac{\text{m}}{\text{s}^2}\][/tex]

(d) Phase:

The phase of the motion is given by the phase angle [tex]\( \frac{\pi}{6} \, \text{rad} \)[/tex] in the displacement equation.

(e) Frequency:

The frequency of the motion is given by the coefficient of [tex]\( t \)[/tex] in the displacement equation. In this case, the frequency is [tex]\( 2\pi \, \frac{\text{rad}}{\text{s}} \)[/tex].

(f) Period:

The period of the motion can be calculated as the reciprocal of the frequency:

[tex]\[ T = \frac{1}{f} \\\\=\frac{1}{2\pi \, \frac{\text{rad}}{\text{s}}} \]\\\\\ T = \frac{1}{2\pi} \, \text{s} \][/tex]

Therefore, the answers to the questions are as follows:

(a) Displacement: [tex]\(-2.325 \, \text{m}\)[/tex]

(b) Velocity: [tex]\(4.28 \, \frac{\text{m}}{\text{s}}\)[/tex]

(c) Acceleration:[tex]\(-48.56 \, \frac{\text{m}}{\text{s}^2}\)[/tex]

(d) Phase: [tex]\( \frac{\pi}{6} \, \text{rad}\)[/tex]

(e) Frequency: [tex]\(2\pi \, \frac{\text{rad}}{\text{s}}\)[/tex]

(f) Period: [tex]\(\frac{1}{2\pi} \, \text{s}\)[/tex]

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Converting Y grams of solid ice to energy would result in fewer joules compared to the same mass of liquid water.

Converting Y grams of liquid water releases more joules than converting the same mass of solid ice due to different energy transformations.

To calculate the amount of energy released when Y grams of liquid water are completely converted, we can use the specific heat capacity of water and the heat of vaporization. Then, we can compare it to the energy released when the same mass of solid ice is converted.

1. Energy released from Y grams of liquid water:

  a) First, we need to consider the energy required to raise the temperature of the water from its initial temperature to its boiling point (100°C).

  Energy = mass × specific heat capacity × temperature change

  Since we are converting the water completely, the final temperature will be the boiling point.

  Energy = Y grams × 4.18 J/g°C × (100°C - initial temperature)

  b) Next, we need to account for the energy required to convert the liquid water at its boiling point to water vapor without a change in temperature. This is known as the heat of vaporization.

  Energy = mass × heat of vaporization

  Energy = Y grams × 2260 J/g (approximate heat of vaporization for water)

  The total energy released when Y grams of liquid water are completely converted would be the sum of the energy calculated in steps (a) and (b).

2. Energy released from Y grams of solid ice:

  When the same mass of solid ice is completely converted, it undergoes two energy transformations:

  a) Energy required to raise the temperature of ice from its initial temperature to its melting point (0°C).

  Energy = mass × specific heat capacity × temperature change

  Energy = Y grams × 2.09 J/g°C × (0°C - initial temperature)

  b) Energy required to convert the solid ice at its melting point to liquid water without a change in temperature. This is also known as the heat of fusion.

  Energy = mass × heat of fusion

  Energy = Y grams × 334 J/g (approximate heat of fusion for ice)

  The total energy released when Y grams of solid ice are completely converted would be the sum of the energy calculated in steps (a) and (b).

Comparing the energy released from Y grams of liquid water to that released from Y grams of solid ice, we find that the energy released from the conversion of liquid water to vapor is significantly greater than the energy released from the conversion of solid ice to liquid water. This is because the heat of vaporization (2260 J/g) is much larger than the heat of fusion (334 J/g). Therefore, converting Y grams of solid ice to energy would result in fewer joules compared to the same mass of liquid water.

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The magnetic field has to be 122.5 × 10⁻⁴ T to support the weight of the maglev train. The final intensity of light is 57.9 W/m² after it passes through the three polarizers.

24) Maglev trains are those trains which work on the principle of magnetic levitation. Magnetic levitation is a phenomenon by which an object is suspended above a surface without any physical support from below. In the case of maglev trains, this is achieved by the use of strong electromagnets which repel the metal rails and keep the train afloat.

If we assume the maglev train to be like a long wire, then it is experiencing a force due to the magnetic field produced by the current flowing through it and the magnetic field of the earth. The magnetic force can be calculated as below:

F = BIL, where

F = magnetic force

B = magnetic field

I = current

L = length of the conductor

Substituting the values in the above formula, we get

F = B × 500 × 120= 60,000 B

As the train is levitating, the magnetic force experienced by the train is equal to its weight. Therefore,60,000 B = mg ⇒ B = \(\frac{mg}{60000}\)

where m = mass of the train = 75,000 kg, g = acceleration due to gravity = 9.8 m/s²B = \(\frac{75000 × 9.8}{60000}\) = 122.5 × 10⁻⁴ T

Thus, the magnetic field has to be 122.5 × 10⁻⁴ T to support the weight of the maglev train.

25)The intensity of light after it passes through the first polarizer is given by:

I₁ = I₀cos² θ, where, I₀ = initial intensity of the light, θ = angle between the polarizer and the plane of polarization,

I₀ = 1050 W/m²θ = 45°I₁ = 1050 × cos² 45°= 525 W/m²

The intensity of light after it passes through the second polarizer is given by:

I₂ = I₁cos² φ, where φ = angle between the second polarizer and the plane of polarization

I₁ = 525 W/m²φ = 45°I₂ = 525 × cos² 45°= 262.5 W/m²

Now, a third polarizer is added, which is tilted at 23° w.r.t the first polarizer.

Therefore, the angle between the third polarizer and the second polarizer is 68° (45° + 23°).

The intensity of light after it passes through the third polarizer is given by:

I₃ = I₂cos² ω, where ω = angle between the third polarizer and the plane of polarization

I₂ = 262.5 W/m²ω = 68°I₃ = 262.5 × cos² 68°= 57.9 W/m²

Therefore, the final intensity of light is 57.9 W/m² after it passes through the three polarizers.

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In the given scenario, a proton is placed between two parallel conducting plates in a vacuum, experiencing an electric field that is moving towards the right. The proton gains a velocity, and we need to determine the electric potential between the two plates.

To calculate the electric potential between the two plates, we can use the equation for the change in electric potential energy, ΔPE = qΔV, where ΔPE is the change in electric potential energy, q is the charge, and ΔV is the change in electric potential.

The work done on the proton is equal to the change in its kinetic energy, which can be calculated using the equation ΔKE = (1/2)mv^2, where ΔKE is the change in kinetic energy, m is the mass of the proton, and v is its final velocity.

By equating the work done on the proton to the change in its kinetic energy, we can solve for the change in electric potential. Since the proton gains energy, the change in electric potential will be negative.

The electric potential between the two plates is then determined by considering the initial and final positions of the proton and calculating the change in electric potential using the given equations.

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The total impedance of the air conditioner is 18.2 Ω and its rms current is 6.2 A.

Given data:

Resistance of air conditioner (R) = 11.6 ohms

Inductive reactance (XL) = 14.1 ohms

Frequency (f) = 50.0 Hz

RMS voltage (Vrms) = 113 V

We need to find the total impedance of the air conditioner and its rms current.

The formula for the total impedance of the air conditioner is:

Z=√(R²+X_L² )

Where

Z is the total impedance of the air conditioner

R is the resistance of the air conditioner

XL is the inductive reactance of the air conditioner

So, total impedance of the air conditioner:

Z = √(11.6² + 14.1² )= 18.2 Ω

The formula for rms current is:

I_rms=V_rms/Z

Where

I_rms is the rms current of the air conditioner

Z is the total impedance of the air conditioner

V_rms is the RMS voltage of the generator

So, the rms current of the air conditioner:

I_rms = V_rms / Z= 113 / 18.2= 6.2 A

Therefore, the total impedance of the air conditioner is 18.2 Ω and its rms current is 6.2 A.

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Given: Velocity of the airplane, v = 247 m/altitude, h = 395 mime of flight, t = ?Distance, d = We know that, the equation of motion for an object under the acceleration due to gravity is given as:-h = 1/2 gt²     .....(i)where g is the acceleration due to gravity and t is the time of flight.

We know that the horizontal distance, d travelled by the airplane is given aside = vt    ......(ii)Now, from equation (i) we can find time of flight t as: -h = 1/2 gt² => 2h/g = t² => t = sqrt(2h/g)

Now, we know that the acceleration due to gravity g is 9.8 m/s². On substituting the given values of h and g we get:-t = sqrt (2 x 395/9.8) => t = 8.019 snow, from equation.

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The relative humidity inside the building, when the air is heated to 40°C without changing the humidity, will be lower than 62.5%.

Relative humidity is a measure of the amount of water vapor present in the air compared to the maximum amount it can hold at a given temperature. In the given scenario, the air temperature is -15°C, and the humidity is 0.001 kg/m³.

To calculate the relative humidity, we need to determine the saturation vapor pressure at -15°C and compare it to the actual vapor pressure, which is determined by the humidity.

Assuming the humidity remains constant when the air is heated to 40°C, the saturation vapor pressure at 40°C will be higher than at -15°C. This means that at 40°C, the same amount of water vapor will result in a lower relative humidity compared to -15°C.

Therefore, the relative humidity inside the building, when the air is heated to 40°C without changing the humidity, will be lower than the relative humidity at -15°C, which is 62.5%.

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the value of the constant "k" in the equation F=kqq/r^2 is 9.00x10^9 Nm^2/C^2.

The equation provided, F=kqq/r^2, represents Coulomb's law, which describes the force between two charged particles. In this equation, "F" represents the electrostatic force between two charges "q" and "q" separated by a distance "r", and "k" is the proportionality constant.To determine the value of "k", we can examine the units of the equation. The force is measured in Newtons (N), the charges are measured in Coulombs (C), and the distance is measured in meters (m).

The SI unit for force is the Newton (N), which is equivalent to kg·m/s^2. The unit for charge is the Coulomb (C), and the unit for distance is the meter (m).By rearranging the equation, we can isolate the constant "k":k = F * r^2 / (q * q).Comparing the units on both sides of the equation, we find that the constant "k" must have units of N·m^2/C^2.Among the given options, the value 9.00x10^9 Nm^2/C^2 corresponds to the correct unit. Therefore, the value of the constant "k" in the equation F=kqq/r^2 is 9.00x10^9 Nm^2/C^2.

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The resulting waveform will have a displacement equal to the sum of their individual displacements at each point.

When waves interfere with each other,

The principle of superposition states that the displacement of the resulting waveform at any point is equal to the algebraic sum of the individual displacements caused by each wave at that point.

In this case, we have two waves, one represented by Figure A and the other by Figure C.

Assuming these waves are traveling in the same medium and have the same frequency, we can determine the resulting waveform by adding the individual displacements at each point.

Let's consider a point in space and time where both waves overlap.

If the amplitude of the wave in Figure A is 4 and the amplitude of the wave in Figure C is 2,

The resulting waveform at that point will have a displacement equal to the sum of the individual displacements, which is

4 + 2 = 6.

The resulting waveform will have a shape and wavelength determined by the characteristics of the individual waves.

The exact form of the resulting waveform will depend on the phase relationship between the waves, which is not specified in the given information.

When the waves in Figure A and Figure C interfere, the resulting waveform will have a displacement equal to the sum of their individual displacements at each point.

The specific shape and wavelength of the resulting waveform will depend on the characteristics and phase relationship of the individual waves.

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When a 601nm light and a 605nm light are to be resolved using a diffraction grating, the number of lines that must be illuminated to resolve the light in the 2nd order is approximately 9589.

When diffraction grating is illuminated with light, it diffracts the light into several beams in various angles. In this process, the distance between lines on a diffraction grating should be less than the wavelength of the light to diffract light into a pattern of bright and dark fringes.

Diffracted order is said to be second when the light bends twice, from the line of the diffraction grating and from the screen.

Here, the difference between the two wavelengths is : 605 nm - 601 nm = 4 nm

To resolve the difference between these two wavelengths, there should be a difference of at least one fringe (or one period).

The formula to calculate the number of fringes or lines illuminated is given as : d sin(θ) = mλ

where,

d is the distance between two lines on the diffraction grating

sin(θ) is the angle at which the light bends

m is the order of diffraction, here m = 2

λ is the wavelength of the light

To resolve the light in the 2nd order, we will substitute the given values in the formula above :

4 × 10⁻⁹ m = d sin(θ) × 2 × 10⁻⁶ m

601 nm and 605 nm light are to be resolved using a diffraction grating.

The number of lines that must be illuminated to resolve the light in the 2nd order is approximately 9589.

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Immediately after the crash, they are moving A) 30 m/s, 37° N of E.

To determine the post-collision velocity and direction, we can use the principles of vector addition.

The first car is traveling east at 18 m/s, which can be represented as a vector with a magnitude of 18 m/s in the positive x-direction (to the right). The second car is traveling north at 24 m/s, which can be represented as a vector with a magnitude of 24 m/s in the positive y-direction (upwards).

After the collision, the cars stick together, which means their velocities combine. To find the resultant velocity, we can add the two velocity vectors using vector addition.

Using the Pythagorean theorem, we can find the magnitude of the resultant velocity:

Resultant velocity magnitude = √((18 m/s)^2 + (24 m/s)^2)

                           = √(324 + 576)

                           = √900

                           = 30 m/s

To find the direction of the resultant velocity, we can use trigonometry. The angle between the resultant velocity vector and the positive x-axis can be determined using the inverse tangent function:

Angle = arctan((24 m/s) / (18 m/s))

     ≈ 53.13°

Since the cars collide at a 90° angle, the post-collision velocity vector will be at a 37° angle relative to the positive x-axis. The direction is 37° north of east.

Therefore, the correct answer is A) 30 m/s, 37° N of E.

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The 0.02 C charge, which has a mass of 85.0 g and is travelling quickly, produces a magnetic field of 0.02 T at point Z.

The field at point Z, due to the 0.02 C charge with a mass of 85.0 g moving fast, can be found using the formula below:

The magnetic field due to a charge in motion can be calculated using the following formula:

B = μ₀ × q × v × sin(θ) / (4πr²), where:

B is the magnetic field

q is the charge

v is the velocity

θ is the angle between the velocity and the line connecting the point of interest to the moving charge

μ₀ is the permeability of free space, which is a constant equal to 4π × 10⁻⁷ T m A⁻¹r is the distance between the point of interest and the moving charge

Given values are

q = 0.02 C

v = unknownθ = 90° (since it is moving perpendicular to the direction to the point Z)

r = 0.01 mm = 0.01 × 10⁻³ m = 10⁻⁵ m

Using the formula, B = μ₀ × q × v × sin(θ) / (4πr²)

Substituting the given values, B = (4π × 10⁻⁷ T m A⁻¹) × (0.02 C) × v × sin(90°) / (4π(10⁻⁵ m)²)

Simplifying, B = (2 × 10⁻⁵) v T where T is the Tesla or Weber per square meter

Thus, the magnetic field at point Z due to the 0.02 C charge with a mass of 85.0 g moving fast is 0.02 μT.

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When measuring the absorption of heat, one must consider the conversion between Kelvin, joules, and calories, as it relates to the specific properties of the food.

(a) Popper's theory of falsification is a cornerstone of science, emphasizing the importance of making testable predictions to validate or refute hypotheses, and even [name of a celebrity] could not escape its scrutiny.

(b) The vibration of the stapes bone in the ear contributes to perceiving different pitches in music, and [name of a singer]'s powerful voice can create a mesmerizing auditory experience.

(c) The harmonic motion of a pendulum, governed by its frequency and influenced by the spring's energy, can be observed by [name of a neighbor] in their backyard.

(d) When measuring heat absorption, the conversion between Kelvin, joules, and calories is crucial, and [name of a food] can release a specific amount of energy upon combustion.

(e) The Pouiselle effect describes the flow of fluids through narrow tubes, where millimeters of diameter can greatly affect the pressure drop across a bar made of any metal.

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Using capacitive reactance of parallel capacitance, the current will increase by a factor of 6/5.

The capacitive reactance is given by the formula:

Xc = 1 / (2πfC)

Where:

Xc is the capacitive reactance,

f is the frequency of the AC signal, and

C is the capacitance.

The current in the circuit

I = V/Xc

I = V×2πfC

For capacitor C1, the current in the circuit is:

I₁= V×2πfC₁

When capacitor C2 is added in series, the current is:

I₂= V×2πf(C₁×C₂)/(C₁+C₂)

I₁/6=V×2πf(C₁×C₂)/(C₁+C₂)

V×2πfC₁/6=V×2πf(C₁×C₂)/(C₁+C₂)

C₁/6= C₁×C₂/(C₁+C₂)

C₁=5C₂

Now if the capacitor is added in parallel, then the current:

I₃=  V×2πf(C₁+C₂)

I₃= V×2πf(C₁ +C₁/5)

I₃=V×2πfC₁×6/5

I₃=6/5×I₁

Therefore, Using capacitive reactance of parallel capacitance, the current will increase by a factor of 6/5.

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The factor by which the current delivered by the generator would have increased is 6.00.

A capacitor (capacitance C₁) is connected across the terminals of an ac generator. Without changing the voltage or frequency of the generator, a second capacitor (capacitance C₂) is added in series with the first one. As a result, the current delivered by the generator decreases by a factor of 6.00. Suppose the second capacitor had been added in parallel with the first one, instead of in series.

Given, Capacitance of capacitor 1, C₁ Capacitance of capacitor 2, C₂ Now, suppose capacitor 2 had been added in parallel with capacitor 1 instead of in series. We have to find out what the resulting change in current would be. Let the final current be I´.

Then, Charge across capacitor 1, Q₁ = CV, Charge across capacitor 2, Q₂ = C₂V, Charge across the two capacitors in series, Q = Q₁ + Q₂ = (C₁ + C₂)V

We know, C = Q/VC₁ + C₂ = Q/V...[1]Also, impedance of the capacitor, Z = 1/ωCThe total impedance is given by the sum of impedances of the two capacitors when they are connected in series.

The total impedance, Z = Z₁ + Z₂ = 1/(ωC₁) + 1/(ωC₂) = (C₁ + C₂)/(ωC₁C₂)As we know, I = V/ZFor the first case, When the capacitors are in series;

The initial current, I₁ = V/Z

Initial impedance, Z₁ = Z = (C₁ + C₂)/(ωC₁C₂)So, I₁ = V/(C₁ + C₂)/(ωC₁C₂) = VωC₁C₂/(C₁ + C₂)So, for the final case, When capacitors are in parallel;

Final impedance, Z₂ = 1/ω(C₁ + C₂)

Total current, I´ = V/Z´Z´ = Z₁||Z₂ = Z₁Z₂/(Z₁ + Z₂)where, Z₁||Z₂ is the impedance of the two capacitors when they are in parallel Z₁||Z₂ = Z₁Z₂/(Z₁ + Z₂)

By substituting the values, we get, Z₁||Z₂ = 1/(ωC₁) * 1/(ωC₂)/(1/(ωC₁) + 1/(ωC₂))I´ = V/Z´ = V/[(1/(ωC₁) * 1/(ωC₂))/(1/(ωC₁) + 1/(ωC₂))]I´ = V/(C₁ + C₂)/(ωC₁C₂)I´ = VωC₁C₂/(C₁ + C₂)

Therefore, the increase in current would be 6.00 times if the second capacitor was added in parallel with the first one.

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(a) The inductance of the coil is approximately 81.33 H.

(b) The energy stored in the coil at this moment is approximately 2.097 × 10^-3 J.

To solve this problem, we can use the formula for the voltage across an inductor in an RL circuit and the formula for the energy stored in an inductor.

(a) The voltage across an inductor in an RL circuit is given by:

V = L * di/dt

where V is the applied voltage, L is the inductance, and di/dt is the rate of change of current with respect to time.

Given:

Applied voltage (V) = 48.8 V

Current (I) = 2.57 mA = 2.57 × 10^-3 A

Time (t) = 4.27 ms = 4.27 × 10^-3 s

Rearranging the formula, we have:

L = V / (di/dt)

Substituting the given values:

[tex]L = 48.8 V / (2.57 × 10^-3 A / 4.27 × 10^-3 s)\\L = 48.8 V / (0.6 A/s)\\L ≈ 81.33 H[/tex]

Therefore, the inductance of the coil is approximately 81.33 H.

(b) The energy stored in an inductor is given by the formula:

E = (1/2) * L * I^2

where E is the energy stored, L is the inductance, and I is the current.

Substituting the given values:

[tex]E = (1/2) * 81.33 H * (2.57 × 10^-3 A)^2\\E = (1/2) * 81.33 H * (6.6049 × 10^-6 A^2)\\E ≈ 2.097 × 10^-3 J[/tex]

Therefore, the energy stored in the coil at this moment is approximately 2.097 × 10^-3 J.

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The coordinate on the x-axis where the electric field produced by the particles is equal to zero is x = 42.6 cm.

To find this coordinate, we need to consider the electric fields produced by both particles. The electric field at any point due to a charged particle is given by Coulomb's law: E = k * (q / r^2), where E is the electric field, k is the Coulomb's constant, q is the charge, and r is the distance from the particle.

Since we want the net electric field to be zero, the electric fields produced by particle 1 and particle 2 should cancel each other out.

Since particle 2 has a charge of -4.00 q1, its electric field will have the opposite direction compared to particle 1. By setting up an equation and solving it, we can find that the distance between the two particles where the net electric field is zero is 42.6 cm.

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As the lunar astronauts moved across the Moon's surface, they were seen to make giant leaps and jumps due to the lower gravity on the Moon's surface. The gravitational pull of the Moon is about one-sixth of the Earth's gravitational pull, which makes it much easier for the astronauts to move around with less effort.

This lower gravity, also known as the weak gravitational field of the Moon, allows for objects to weigh less and have less inertia. As a result, the lunar astronauts were able to take longer strides and jump much higher than they could on Earth.

Moreover, the space suits worn by the astronauts were designed to help them move around on the Moon. They were fitted with special boots that had a rigid sole that prevented them from sinking into the lunar dust. Additionally, the suits had backpacks that supplied them with oxygen to breathe and allowed them to move with ease.

Therefore, the combination of the lower gravity and the design of the spacesuits helped the lunar astronauts move around on the Moon's surface in a seemingly odd fashion, including making giant leaps and jumps.

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In an NP-transistor (NPN transistor), the base is typically made of p-type semiconductor material, while the emitter and collector are made of n-type semiconductor material.

To switch the transistor "ON" and allow current to flow through it, the base-emitter junction needs to be forward-biased. This means that the base terminal should have a higher positive potential than the emitter terminal.

By applying a small positive potential to the base (relative to the emitter) and a large NP-transistor to the collector, the base-emitter junction is forward-biased, allowing current to flow through the transistor and switching it "ON".The correct answer is (A) Applying large negative potential to the collector and small positive potential to the base.

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The magnetic force acting on the proton moving through a magnetic field is  1.0703 × 10⁻¹¹ N.

Given data:Magnitude of magnetic field, B = 0.00669 T,Speed of proton, v = 0.385,

c = 0.385 × 2.998 × 108 m/s,

Charge of proton, e = 1.602 × 10⁻¹⁹ C,

Angle between velocity of proton and magnetic field, θ = 127°.Now, the formula to calculate the magnitude of force on a charged particle due to a magnetic field is F = |q|vBsinθ.

Here, q = charge on the particle = e (elementary charge) |q| = magnitude of charge on the particle = e|v|

speed of the particle = 0.385,

c = 0.385 × 2.998 × 108 m/sB = magnitude of the magnetic field = 0.00669 T,

θ = angle between velocity of the particle and the magnetic field = 127°.

Putting these values in the above equation, we getF = |e|×|v|×|B|×sinθ,

F= 1.602 × 10⁻¹⁹ C × 0.385 × 2.998 × 10⁸ m/s × 0.00669 T × sin(127°),

F = 1.602 × 10⁻¹⁹ × 0.385 × 2.998 × 10⁸ × 0.00669 × 0.9045,

F = 1.0703 × 10⁻¹¹ N.

Therefore, the magnitude of the magnetic force acting on the proton is 1.0703 × 10⁻¹¹ N.

The magnetic force acting on the proton moving through a magnetic field can be calculated using the formula F = |q|vBsinθ. When the value of |e|×|v|×|B|×sinθ is calculated with the given values of velocity, magnetic field and angle, it comes out to be 1.0703 × 10⁻¹¹ N.

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Approximately 1.35 lb-in of work is done compressing the scale when a 90-lb person stands on it. To calculate the work done in compressing the scale, we can use the formula:

Work (W) = (1/2) * k *[tex]x^2[/tex]

where:

k is the spring constant of the scale

x is the displacement (change in length) of the scale

Initial weight (W1) = 240 lb

Initial compression (x1) = 0.080 in

Final weight (W2) = 90 lb

To find the spring constant (k), we need to determine the force exerted by the scale for the initial compression.

Using Hooke's Law:

F = k * x

The force exerted by the 240-lb person is equal to their weight:

F1 = 240 lb

Therefore:

240 lb = k * 0.080 in

Converting inches to pounds (using the conversion factor of 1 lb/in):

240 lb = k * 0.080 lb/in

k = 240 lb / 0.080 lb/in

k = 3000 lb/in

Now that we have the spring constant, we can calculate the work done when the 90-lb person stands on the scale.

Using Hooke's Law:

[tex]F_2 = k * x_2[/tex]

where:

[tex]F_2[/tex]is the force exerted by the 90-lb person

[tex]x_2[/tex] is the displacement (change in length) for the 90-lb person

We need to find[tex]x_2,[/tex] the difference in compression between the two scenarios.

Using the proportion:

[tex]x_1/W_1 = x_2/W_2[/tex]

0.080 in / 240 lb =[tex]x_2[/tex]/ 90 lb

Simplifying:

[tex]x_2[/tex]= (0.080 in * 90 lb) / 240 lb

[tex]x_2[/tex] ≈ 0.030 in

Now we can calculate the work done:

W = (1/2) * k * [tex]x_2^2[/tex]

W = (1/2) * 3000 lb/in * ([tex]0.030 in)^2[/tex]

W ≈ 1.35 lb-in

Therefore, approximately 1.35 lb-in of work is done compressing the scale when a 90-lb person stands on it.

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(a) The translational kinetic energy of the cylinder's centre of gravity is 729.63 J.

(b) The rotational kinetic energy about its centre of gravity is 729.63 J.

(c) The total kinetic energy of the cylinder is 1,459.26 J.

(a) To find the translational kinetic energy, we use the formula KE_trans = (1/2) * m * v^2, where m is the mass of the cylinder and v is the speed of its centre of gravity. Substituting the given values, KE_trans = (1/2) * 12.2 kg * (11.7 m/s)^2 = 729.63 J.

(b) The rotational kinetic energy about the centre of gravity can be calculated using the formula KE_rot = (1/2) * I * ω^2, where I is the moment of inertia and ω is the angular velocity. Since the cylinder rolls without slipping, we can relate the linear velocity of the centre of gravity to the angular velocity by v = ω * R, where R is the radius of the cylinder.

Rearranging the equation, we have ω = v / R. The moment of inertia for a cylinder rotating about its central axis is I = (1/2) * m * R^2. Substituting the values, KE_rot = (1/2) * (1/2) * 12.2 kg * (11.7 m/s / R)^2 = 729.63 J.

(c) The total kinetic energy is the sum of the translational and rotational kinetic energies, which gives us 1,459.26 J.

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(a) The electric potential on the z-axis, perpendicular to and through the center of the disk, is given by V(z>0) = (kQ/2aε₀) and V(z<0) = (-kQ/2aε₀), where k is the Coulomb's constant, Q is the charge distributed on the disk, a is the radius of the disk, and ε₀ is the vacuum permittivity.

(b) The electric potential in all regions surrounding the disk is given by V(r) = (kQ/2ε₀) * (1/r), where r is the distance from the center of the disk and k, Q, and ε₀ have their previous definitions.

(a) To find the electric potential on the z-axis, we consider the disk as a collection of infinitesimally small charge elements. Using the principle of superposition, we integrate the electric potential contributions from each charge element over the entire disk. The result is V(z>0) = (kQ/2aε₀) for z > 0, and V(z<0) = (-kQ/2aε₀) for z < 0. These formulas indicate that the potential is positive above the disk and negative below the disk.

(b) To find the electric potential in all regions surrounding the disk, we use the formula for the electric potential due to a uniformly charged disk. The formula is V(r) = (kQ/2ε₀) * (1/r), where r is the distance from the center of the disk. This formula shows that the electric potential decreases as the distance from the center of the disk increases. Both regions of r > a and r < a are included, indicating that the potential is influenced by the charge distribution on the entire disk.

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To solve this problem using the principle of conservation of momentum. So, the velocity of the second skater is approximately 0.609 m/s in the opposite direction (north).

Given:

Mass of the first skater (m1) = 47.0 kg

Velocity of the first skater (v1) = 0.645 m/s south

Mass of the second skater (m2) = 50 kg

Velocity of the second skater (v2) = ?

According to the principle of conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

Initial momentum = Final momentum

The initial momentum of the system can be calculated by multiplying the mass of each skater by their respective velocities:

Initial momentum = (m1 * v1) + (m2 * v2)

The final momentum of the system can be calculated by considering that after pushing off against each other, the two skaters move in opposite directions with their respective velocities:

Final momentum = (m1 * (-v1)) + (m2 * v2)

Setting the initial momentum equal to the final momentum, we have:

(m1 * v1) + (m2 * v2) = (m1 * (-v1)) + (m2 * v2)

Rearranging the equation and solving for v2:

2 * (m2 * v2) = m1 * v1 - m1 * (-v1)

2 * (m2 * v2) = m1 * v1 + m1 * v1

2 * (m2 * v2) = 2 * m1 * v1

m2 * v2 = m1 * v1

v2 = (m1 * v1) / m2

Substituting the given values, we can calculate the velocity of the second skater:

v2 = (47.0 kg * 0.645 m/s) / 50 kg

v2 ≈ 0.609 m/s

Therefore, the velocity of the second skater is approximately 0.609 m/s in the opposite direction (north).

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